Supertrick to Find Bond Order | Part -1| Jee Mains, Advance | AIIMS | NEET | BITSAT | REE Video
Hello Guys
Once again, we are available with one of the most important topics for jee and Medical.
Shortcut Trick for Bond Order
Bond Order questions are very common in JEE and other entrance exams. In this post, I will share a very useful trick that helps to solve questions based on bond order very quickly. But first…
What is Bond Order?
You know what Bond Order is, don’t you? If you do, skip the following paragraph. If you don’t read the following few lines carefully.
Bond order is a number that tells us how strong the bond between two atoms forming a molecule is. If the bond order is high, the bond is strong and so the molecule is stable. If the bond order is low, the molecule is unstable.
How do we calculate Bond Order?
There are many methods to finding bond order. One of the most famous and most used formulas states:
Bond Order=1/2(Nb–Na)
where, Nb = No. of electrons in Bonding M.O.
and Na = No. of electrons in Anti-Bonding M.O.
This is NOT the best method for finding bond order in questions which are asked in JEE or other entrance exams. Why?
This is NOT the best method for finding bond order in questions which are asked in JEE or other entrance exams. Why?
1. You need to properly find the number of electrons in bonding molecular orbitals and antibonding molecular orbitals.
2. It takes a lot of time
How should you calculate bond order?
With a little memorization and practice, you can find out the bond order of a species just by looking at it. The method that we will be using IS NOT applicable everywhere, but it works in 99% of JEE problems. So, you see the worth in learning it.
This method will work for any species that have between 10 and 18 electrons. Most problems asked in JEE have electrons between 10 and 18, therefore it is very handy.
First, what you need to remember is this: N2 has 14 electrons and its bond order is 3. Every electron added or subtracted to 14, reduces the bond order by 0.5.
For example, if the number of electrons is 15, then the bond order is 3 – 0.5 = 2.5. Done!
Steps:
Just count the total number of electrons and find the difference from 14. Call it ‘n’.
Bond order = 3 – 0.5n
Points to e remember:
Bond order is directly proportional to Bond dissociation energy and stability but inversely proportional to bond length.
We Hope you will enjoy our lecture.
thanks,
team IITian Explains
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